libc: Remove support for pre-C99 C standards
Reviewed by: jhb Differential Revision: https://reviews.freebsd.org/D43254
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committed by
John Baldwin
parent
4f854658c5
commit
7c7299df76
+1
-29
@@ -41,34 +41,6 @@ div(int num, int denom)
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r.quot = num / denom;
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r.rem = num % denom;
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#if !defined(__STDC_VERSION__) || (__STDC_VERSION__ < 199901L)
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/*
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* The ANSI standard says that |r.quot| <= |n/d|, where
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* n/d is to be computed in infinite precision. In other
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* words, we should always truncate the quotient towards
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* 0, never -infinity.
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*
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* Machine division and remainer may work either way when
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* one or both of n or d is negative. If only one is
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* negative and r.quot has been truncated towards -inf,
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* r.rem will have the same sign as denom and the opposite
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* sign of num; if both are negative and r.quot has been
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* truncated towards -inf, r.rem will be positive (will
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* have the opposite sign of num). These are considered
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* `wrong'.
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*
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* If both are num and denom are positive, r will always
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* be positive.
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*
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* This all boils down to:
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* if num >= 0, but r.rem < 0, we got the wrong answer.
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* In that case, to get the right answer, add 1 to r.quot and
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* subtract denom from r.rem.
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*/
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if (num >= 0 && r.rem < 0) {
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r.quot++;
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r.rem -= denom;
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}
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#endif
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return (r);
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}
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@@ -36,11 +36,6 @@ imaxdiv(intmax_t numer, intmax_t denom)
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retval.quot = numer / denom;
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retval.rem = numer % denom;
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#if !defined(__STDC_VERSION__) || (__STDC_VERSION__ < 199901L)
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if (numer >= 0 && retval.rem < 0) {
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retval.quot++;
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retval.rem -= denom;
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}
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#endif
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return (retval);
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}
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@@ -43,11 +43,6 @@ ldiv(long num, long denom)
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r.quot = num / denom;
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r.rem = num % denom;
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#if !defined(__STDC_VERSION__) || (__STDC_VERSION__ < 199901L)
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if (num >= 0 && r.rem < 0) {
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r.quot++;
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r.rem -= denom;
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}
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#endif
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return (r);
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}
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@@ -36,11 +36,6 @@ lldiv(long long numer, long long denom)
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retval.quot = numer / denom;
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retval.rem = numer % denom;
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#if !defined(__STDC_VERSION__) || (__STDC_VERSION__ < 199901L)
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if (numer >= 0 && retval.rem < 0) {
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retval.quot++;
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retval.rem -= denom;
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}
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#endif
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return (retval);
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}
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